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I found this way to achieve what you're asking for. I'll provide a full example below: site_url = 'companyname.sharepoint.com:/site_name'
drive_name = 'Example Folder'
site = await self.client.sites.by_site_id(site_url).get()
drives = await self.client.sites.by_site_id(site.id).drives.get()
drive = None
for drive in drives.value:
if drive.name == drive_name:
drive = drive
if drive is not None:
folder = await self.client.drives.by_drive_id(drive.id).items.by_drive_item_id('root:/dira/dirb:/children').get()
for file in folder.additional_data['value']:
print(file['name'])
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Let's say I have a directory at sharepoint like below, and i like to list all files under "dira/dirb"
sites/site_id/drives/drive_id/dira/dirb/....
I could get site_id and drive_id via source code,
But not found a way to list all files(or directories) under "dira/dirb", any advice?
Thanks
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