Set.prototype.delete()

Baseline Widely available

This feature is well established and works across many devices and browser versions. It’s been available across browsers since 2015年7月.

delete() 方法會一個 Set 物件中移除指定元素。

嘗試一下

const set1 = new Set();
set1.add({ x: 10, y: 20 }).add({ x: 20, y: 30 });

// Delete any point with `x > 10`.
set1.forEach((point) => {
  if (point.x > 10) {
    set1.delete(point);
  }
});

console.log(set1.size);
// Expected output: 1

語法

mySet.delete(value);

參數'

value

要從 Set 物件中移除的值。

回傳值

true 如果成功從 Set 物件中移除；反之 false。

範例

使用 delete 方法

js
var mySet = new Set();
mySet.add("foo");

mySet.delete("bar"); // Returns false. No "bar" element found to be deleted.
mySet.delete("foo"); // Returns true.  Successfully removed.

mySet.has("foo"); // Returns false. The "foo" element is no longer present.

下方展示了如何從一個 Set 中移除物件。

js
var setObj = new Set(); // Create a New Set.

setObj.add({ x: 10, y: 20 }); // Add object in the set.

setObj.add({ x: 20, y: 30 }); // Add object in the set.

// Delete any point with `x > 10`.
setObj.forEach(function (point) {
  if (point.x > 10) {
    setObj.delete(point);
  }
});

規範

Specification

ECMAScript® 2027 Language Specification
# sec-set.prototype.delete

瀏覽器相容性

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參見

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This page was last modified on 2025年7月14日 by MDN contributors.

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Set.prototype.delete()

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