Array.prototype.sort() - JavaScript | MDN

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Array.prototype.sort()

Baseline Widely available

This feature is well established and works across many devices and browser versions. It’s been available across browsers since July 2015.

The sort() method of Array instances sorts the elements of an array in place and returns the reference to the same array, now sorted. The default sort order is ascending, built upon converting the elements into strings, then comparing their sequences of UTF-16 code unit values.

The time and space complexity of the sort cannot be guaranteed as it depends on the implementation.

To sort the elements in an array without mutating the original array, use toSorted().

Try it

const months = ["March", "Jan", "Feb", "Dec"];
months.sort();
console.log(months);
// Expected output: Array ["Dec", "Feb", "Jan", "March"]

const array = [1, 30, 4, 21, 100000];
array.sort();
console.log(array);
// Expected output: Array [1, 100000, 21, 30, 4]

Syntax

js
sort()
sort(compareFn)

Parameters

compareFn Optional

A function that determines the order of the elements. The function is called with the following arguments:

The first element for comparison. Will never be undefined.

The second element for comparison. Will never be undefined.

It should return a number where:

A negative value indicates that a should come before b.
A positive value indicates that a should come after b.
Zero or NaN indicates that a and b are considered equal.

To memorize this, remember that (a, b) => a - b sorts numbers in ascending order.

If omitted, the array elements are converted to strings, then sorted according to each character's Unicode code point value.

Return value

The reference to the original array, now sorted. Note that the array is sorted in place, and no copy is made.

Description

If compareFn is not supplied, all non-undefined array elements are sorted by converting them to strings and comparing strings in UTF-16 code units order. For example, "banana" comes before "cherry". In a numeric sort, 9 comes before 80, but because numbers are converted to strings, "80" comes before "9" in the Unicode order. All undefined elements are sorted to the end of the array.

The sort() method preserves empty slots. If the source array is sparse, the empty slots are moved to the end of the array, and always come after all the undefined.

Note: In UTF-16, Unicode characters above \uFFFF are encoded as two surrogate code units, of the range \uD800 - \uDFFF. The value of each code unit is taken separately into account for the comparison. Thus the character formed by the surrogate pair \uD855\uDE51 will be sorted before the character \uFF3A.

If compareFn is supplied, all non-undefined array elements are sorted according to the return value of the compare function (all undefined elements are sorted to the end of the array, with no call to compareFn).

compareFn(a, b) return value sort order

> 0	sort a after b, e.g., [b, a]
< 0	sort a before b, e.g., [a, b]
=== 0	keep original order of a and b

So, the compare function has the following form:

js
function compareFn(a, b) {
  if (a is less than b by some ordering criterion) {
    return -1;
  } else if (a is greater than b by the ordering criterion) {
    return 1;
  }
  // a must be equal to b
  return 0;
}

More formally, the comparator is expected to have the following properties, in order to ensure proper sort behavior:

Pure: The comparator does not mutate the objects being compared or any external state. (This is important because there's no guarantee when and how the comparator will be called, so any particular call should not produce visible effects to the outside.)
Stable: The comparator returns the same result with the same pair of input.
Reflexive: compareFn(a, a) === 0.
Anti-symmetric: compareFn(a, b) and compareFn(b, a) must both be 0 or have opposite signs.
Transitive: If compareFn(a, b) and compareFn(b, c) are both positive, zero, or negative, then compareFn(a, c) has the same positivity as the previous two.

A comparator conforming to the constraints above will always be able to return all of 1, 0, and -1, or consistently return 0. For example, if a comparator only returns 1 and 0, or only returns 0 and -1, it will not be able to sort reliably because anti-symmetry is broken. A comparator that always returns 0 will cause the array to not be changed at all, but is reliable nonetheless.

The default lexicographic comparator satisfies all constraints above.

To compare numbers instead of strings, the compare function can subtract b from a. The following function will sort the array in ascending order (if it doesn't contain NaN):

js
function compareNumbers(a, b) {
  return a - b;
}

The sort() method is generic. It only expects the this value to have a length property and integer-keyed properties. Although strings are also array-like, this method is not suitable to be applied on them, as strings are immutable.

Examples

Creating, displaying, and sorting an array

The following example creates four arrays and displays the original array, then the sorted arrays. The numeric arrays are sorted without a compare function, then sorted using one.

js
const stringArray = ["Blue", "Humpback", "Beluga"];
const numberArray = [40, 1, 5, 200];
const numericStringArray = ["80", "9", "700"];
const mixedNumericArray = ["80", "9", "700", 40, 1, 5, 200];

function compareNumbers(a, b) {
  return a - b;
}

stringArray.join(); // 'Blue,Humpback,Beluga'
stringArray.sort(); // ['Beluga', 'Blue', 'Humpback']

numberArray.join(); // '40,1,5,200'
numberArray.sort(); // [1, 200, 40, 5]
numberArray.sort(compareNumbers); // [1, 5, 40, 200]

numericStringArray.join(); // '80,9,700'
numericStringArray.sort(); // ['700', '80', '9']
numericStringArray.sort(compareNumbers); // ['9', '80', '700']

mixedNumericArray.join(); // '80,9,700,40,1,5,200'
mixedNumericArray.sort(); // [1, 200, 40, 5, '700', '80', '9']
mixedNumericArray.sort(compareNumbers); // [1, 5, '9', 40, '80', 200, '700']

Sorting array of objects

Arrays of objects can be sorted by comparing the value of one of their properties.

js
const items = [
  { name: "Edward", value: 21 },
  { name: "Sharpe", value: 37 },
  { name: "And", value: 45 },
  { name: "The", value: -12 },
  { name: "Magnetic", value: 13 },
  { name: "Zeros", value: 37 },
];

// sort by value
items.sort((a, b) => a.value - b.value);

// sort by name
items.sort((a, b) => {
  const nameA = a.name.toUpperCase(); // ignore upper and lowercase
  const nameB = b.name.toUpperCase(); // ignore upper and lowercase
  if (nameA < nameB) {
    return -1;
  }
  if (nameA > nameB) {
    return 1;
  }

  // names must be equal
  return 0;
});

Sorting non-ASCII characters

For sorting strings with non-ASCII characters, i.e., strings with accented characters (e, é, è, a, ä, etc.), strings from languages other than English, use String.prototype.localeCompare(). This function can compare those characters so they appear in the right order.

js
const items = ["réservé", "premier", "communiqué", "café", "adieu", "éclair"];
items.sort((a, b) => a.localeCompare(b));

// items is ['adieu', 'café', 'communiqué', 'éclair', 'premier', 'réservé']

Sorting with map

The compareFn can be invoked multiple times per element within the array. Depending on the compareFn's nature, this may yield a high overhead. The more work a compareFn does and the more elements there are to sort, it may be more efficient to use map() for sorting. The idea is to traverse the array once to extract the actual values used for sorting into a temporary array, sort the temporary array, and then traverse the temporary array to achieve the right order.

js
// the array to be sorted
const data = ["delta", "alpha", "charlie", "bravo"];

// temporary array holds objects with position and sort-value
const mapped = data.map((v, i) => ({ i, value: someSlowOperation(v) }));

// sorting the mapped array containing the reduced values
mapped.sort((a, b) => {
  if (a.value > b.value) {
    return 1;
  }
  if (a.value < b.value) {
    return -1;
  }
  return 0;
});

const result = mapped.map((v) => data[v.i]);

There is an open source library available called mapsort which applies this approach.

sort() returns the reference to the same array

The sort() method returns a reference to the original array, so mutating the returned array will mutate the original array as well.

js
const numbers = [3, 1, 4, 1, 5];
const sorted = numbers.sort((a, b) => a - b);
// numbers and sorted are both [1, 1, 3, 4, 5]
sorted[0] = 10;
console.log(numbers[0]); // 10

In case you want sort() to not mutate the original array, but return a shallow-copied array like other array methods (e.g., map()) do, use the toSorted() method. Alternatively, you can do a shallow copy before calling sort(), using the spread syntax or Array.from().

js
const numbers = [3, 1, 4, 1, 5];
// [...numbers] creates a shallow copy, so sort() does not mutate the original
const sorted = [...numbers].sort((a, b) => a - b);
sorted[0] = 10;
console.log(numbers[0]); // 3

Sort stability

Since version 10 (or ECMAScript 2019), the specification dictates that Array.prototype.sort is stable.

For example, say you had a list of students alongside their grades. Note that the list of students is already pre-sorted by name in alphabetical order:

js
const students = [
  { name: "Alex", grade: 15 },
  { name: "Devlin", grade: 15 },
  { name: "Eagle", grade: 13 },
  { name: "Sam", grade: 14 },
];

After sorting this array by grade in ascending order:

students.sort((firstItem, secondItem) => firstItem.grade - secondItem.grade);

The students variable will then have the following value:

js
[
  { name: "Eagle", grade: 13 },
  { name: "Sam", grade: 14 },
  { name: "Alex", grade: 15 }, // original maintained for similar grade (stable sorting)
  { name: "Devlin", grade: 15 }, // original maintained for similar grade (stable sorting)
];

It's important to note that students that have the same grade (for example, Alex and Devlin), will remain in the same order as before calling the sort. This is what a stable sorting algorithm guarantees.

Before version 10 (or ECMAScript 2019), sort stability was not guaranteed, meaning that you could end up with the following:

js
[
  { name: "Eagle", grade: 13 },
  { name: "Sam", grade: 14 },
  { name: "Devlin", grade: 15 }, // original order not maintained
  { name: "Alex", grade: 15 }, // original order not maintained
];

Sorting with non-well-formed comparator

If a comparing function does not satisfy all of purity, stability, reflexivity, anti-symmetry, and transitivity rules, as explained in the description, the program's behavior is not well-defined.

For example, consider this code:

js
const arr = [3, 1, 4, 1, 5, 9];
const compareFn = (a, b) => (a > b ? 1 : 0);
arr.sort(compareFn);

The compareFn function here is not well-formed, because it does not satisfy anti-symmetry: if a > b, it returns 1; but by swapping a and b, it returns 0 instead of a negative value. Therefore, the resulting array will be different across engines. For example, V8 (used by Chrome, Node.js, etc.) and JavaScriptCore (used by Safari) would not sort the array at all and return [3, 1, 4, 1, 5, 9], while SpiderMonkey (used by Firefox) will return the array sorted ascendingly, as [1, 1, 3, 4, 5, 9].

However, if the compareFn function is changed slightly so that it returns -1 or 0:

js
const arr = [3, 1, 4, 1, 5, 9];
const compareFn = (a, b) => (a > b ? -1 : 0);
arr.sort(compareFn);

Then V8 and JavaScriptCore sorts it descendingly, as [9, 5, 4, 3, 1, 1], while SpiderMonkey returns it as-is: [3, 1, 4, 1, 5, 9].

Due to this implementation inconsistency, you are always advised to make your comparator well-formed by following the five constraints.

Using sort() on sparse arrays

Empty slots are moved to the end of the array.

js
console.log(["a", "c", , "b"].sort()); // ['a', 'b', 'c', empty]
console.log([, undefined, "a", "b"].sort()); // ["a", "b", undefined, empty]

Calling sort() on non-array objects

The sort() method reads the length property of this. It then collects all existing integer-keyed properties in the range of 0 to length - 1, sorts them, and writes them back. If there are missing properties in the range, the corresponding trailing properties are deleted, as if the non-existent properties are sorted towards the end.

js
const arrayLike = {
  length: 3,
  unrelated: "foo",
  0: 5,
  2: 4,
};
console.log(Array.prototype.sort.call(arrayLike));
// { '0': 4, '1': 5, length: 3, unrelated: 'foo' }